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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Evgeny Shilov
Evgeny Shilov
21,283 Points
Posted by Evgeny Shilov
Evgeny Shilov
21,283 Points

Help with the exercise, please

My code seems to be working fine, but it still reports the issue:

"Bummer! Hmm, didn't get the expected output. Be sure you're not splitting only on spaces!"

Could you help pls?

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
import re

def word_count(some_string):
    some_dict = {}
    list_of_words = re.split(' |,|\.', some_string.lower())

    for i in list_of_words:
        try:
            some_dict[i] += 1
        except KeyError:
            some_dict[i] = 1

    print(some_dict)
    return some_dict

1 Answer

Umesh Ravji
Umesh Ravji
42,386 Points
Umesh Ravji
Umesh Ravji
42,386 Points

I got that same message and it took me a while to work out what exactly it was looking for.

I had spent a while wondering why words = string.split(' ') wasn't working and was getting the same issue as you, and do feel like the message isn't really pointing anyone in the right direction.

Since you had the initiative to try a regular expression, I am sure I don't have to explain why words = re.split('\s', string) :)

Evgeny Shilov
Evgeny Shilov
21,283 Points
Evgeny Shilov
Evgeny Shilov
21,283 Points

Worked! Thank you, Umesh!! The correct answer is quite surprising)