Here is my attempt at it. If I made mistakes please let me know so I can learn from my mistakes.

Question

function randomNumber(a, b) {
    if (isNaN(a) || isNaN(b)) {
        throw new Error("one or both numbers in your function call is not a number");
    }else{
        var num = Math.floor(Math.random() * (a - b -1) + (b + 1));
    }
    document.write(num); //code test
    return num;
}
console.log(randomNumber(23, "one"));

Answer 1 · 2018-07-14T21:50:37Z

July 14, 2018 9:50pm

Hey Raul, it looks good to me.

When I run the code as is, I get the error message that you entered, "one or both numbers in your function call is not a number," which is good because you're passing in a string when you call your function, so the if statement is correctly identifying that it was passed an argument that was not a number.

Then when I change the "one" to a number, a seemingly random number, between the two numbers passed into the function, is logged to my console and written on the page, so the else statement is executing, storing our "random" number in "num", and your function is correctly returning the "num" variable.

So, good work!

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Raul Cisneros

Raul Cisneros

Here is my attempt at it. If I made mistakes please let me know so I can learn from my mistakes.

1 Answer

Matthew Lanin

Matthew Lanin