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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Random Number Challenge Solution

Thiago Reis
Thiago Reis
2,247 Points
Posted by Thiago Reis
Thiago Reis
2,247 Points

Here's my solution!

function random (a, b) {
  var result = Math.floor(Math.random() *  + b + 1);
  if (result >= a){
  alert(result);
  } else {(random();)
    }
 }

var numberOne = prompt('Type a low number');
var numberTwo = prompt('Type a big number');
random(numberOne, numberTwo);

2 Answers

Daniel Newman
PLUS
Daniel Newman
Courses Plus Student 10,715 Points
Daniel Newman
Daniel Newman
Courses Plus Student 10,715 Points

Check your link. It doesn't work.

Daniel Newman
PLUS
Daniel Newman
Courses Plus Student 10,715 Points
Daniel Newman
Daniel Newman
Courses Plus Student 10,715 Points

If you need random number between "a" and "b" you know "space" between them: "b - a". Next you should choose randomly something and summarize it with lower number: random() * (b-a) + a. But this way is "exclusive" case of getting "b".

We need to add 1 to make out function "inclusive" maximal(big) value also:

function random (a, b) {
  var result = Math.floor(Math.random() * ( b - a + 1) + a);

The next part is strange. I don't remember task, but you try to insure that random number is not... bigger then or equal lower one? It's always will be greater or equal by code you do.

  if (result >= a) {
    alert(result);

This part will never happens, but if it will both "a" and "b" is undefined, because you have no parameters inside random function. And the parenthesis is useless also.

  } else {
    (random();)
  }
}

And this part is ok.

var numberOne = prompt('Type a low number');
var numberTwo = prompt('Type a big number');
random(numberOne, numberTwo);