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JavaScript AJAX Basics AJAX Concepts Finish the AJAX Request

hi guys. So i written the code that i think is correct and variable xhr is not good....

can anyone help me please

app.js
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
  if (request.readyState === 4) {
    document.getElementById("footer").innerHTML = request.responseText;
  }
};
xhr.open('GET', 'footer.html');
index.html
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="footer"></div>
</body>
</html>

1 Answer

Jeff Muday
MOD
Jeff Muday
Treehouse Moderator 28,720 Points

The variable xhr is not declared. You need to use the request variable instead.

var request = new XMLHttpRequest();
request.onreadystatechange = function () {
  if (request.readyState === 4) {
    document.getElementById("footer").innerHTML = request.responseText;
  }
};
request.open('GET', 'footer.html');

thx!