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Nilay Jain
4,146 PointsHi, I am getting the error -'Bummer! Hmm, didn't get the expected output. Be sure you're not splitting only on spaces!'?
I see that my code includes splitting on the spaces. Could you please let me know what else is required in the challenge?
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(value):
list1 = value.lower().split(" ")
dict1 = {}
for each in list1:
dict1.update({each : list1.count(each)})
return dict1
2 Answers
Andrew Mlamba
15,642 PointsIssue seems to be with the separator you have used in the .split() method. I removed it and the same code passed the grader tests.
Is there anyone who can tell us the impact of having a separator or not having it, in this case.
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(value):
list1 = value.lower().split(" ") # <-- remove the separator so as to pass a default
dict1 = {}
for each in list1:
dict1.update({each : list1.count(each)})
return dict1
Iain Simmons
Treehouse Moderator 32,305 PointsThe default splitting behaviour (if you don't pass a separator argument) is to split on consecutive whitespace characters.
See the Python docs