Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialOfek Salama
Full Stack JavaScript Techdegree Student 1,737 Pointshi' I tried every thing and It dosnt help. this is my answer: for (prop in shanghai){ console.log(prop) }
for (prop in shanghai){ console.log(prop) } why this dosnt print the prop to the console? I tried also this: for (prop in shanghai){ console.log(shanghai[prop]) } and it dosnt work. thank you
var shanghai = {
population: 14.35e6,
longitude: '31.2000 N',
latitude: '121.5000 E',
country: 'CHN'
};
for (prop in shanghai){
console.log(prop)
}
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript Objects</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
2 Answers
Ofek Salama
Full Stack JavaScript Techdegree Student 1,737 Pointshi, maby you know why this dosnt make a for in loop for me?: for (prop in shanghai){ console.log(prop) } i tried also : for (prop in shanghai){ console.log(shanghai[prop]) } also dosnt work. thank you Ofek
Mark Sebeck
Treehouse Moderator 37,799 PointsHi Ofek. You are close. You forgot to declare prop. You need to put var in front of prop in the for loop.