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PHP PHP Basics (Retired) PHP Conditionals & Loops Conditionals Challenge

Posted by Wiktor Głowacki
Wiktor Głowacki
699 Points

Hi looks like I found a bug in challenge test

Hi, my challenge is: Under the variable $name create a if statement that test to see that the $name variable is set to the string 'Mike'.

so my code is:

$name = 'Mike';
if ($name = "Mike"){

}

but course checker is saying: Bummer! I cannot see your 'if' statement.

Is this a bug?

4 Answers

Erik McClintock
Erik McClintock
45,783 Points
Erik McClintock
Erik McClintock
45,783 Points

Wiktor,

There has been a bug on this challenge, but currently, you have an error in your code. You are currently using one equals sign in your IF statement, which is what you use to assign a value, not to check equality between two values. You need to replace the single equals with a double or triple equals sign in your code to have the correct answer.

if($name == 'Mike') {
}

//or

if($name === 'Mike') {
}

Try adding an equals sign and see if you pass. If you don't, then the bug is still present on this challenge.

Erik

Wiktor Głowacki
Wiktor Głowacki
699 Points
Wiktor Głowacki
Wiktor Głowacki
699 Points

Thanks Erik

I did try with two equals sign but there was the same error displayed. What I just discovered now is:

  • I typed if($name=='Mike'){} - chalenge passed
  • I typed if ($name=='Mike'){} - chalenge failed
  • I removed space between if and ( and recheck challenge - failed again
Jason Anello
Jason Anello
Courses Plus Student 94,610 Points

Hi Wiktor,

I thought maybe you found the secret but I can't duplicate your results. Anyway, I don't think the challenge should require that it's all placed on one line.

This challenge and the foreach one which you've already discovered are currently down.

The staff are working on it.

Wiktor Głowacki
Wiktor Głowacki
699 Points
Wiktor Głowacki
Wiktor Głowacki
699 Points

The same story on loop challenge:

Using a foreach, create a loop that goes through each of the names in the $names array.

Bummer! I do not see a foreach statement

<?php $names = array('Mike', 'Chris', 'Jane', 'Bob'); foreach($names as $name) { } ?>

Gelson Luiz Sabino Junior
Gelson Luiz Sabino Junior
3,153 Points
Gelson Luiz Sabino Junior
Gelson Luiz Sabino Junior
3,153 Points

It is no bugged.

The RIGHT answer is:

<?php

$name = "Mike";

if($name == "Mike") { echo "Hi, I am " . $name . "!"; }

?>