Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Shopping List App Break

Alex Kräuchi
Alex Kräuchi
4,807 Points

Hi! What seems to be the problem with my solution

I should be able to exit the loop with this IF statement no?

breaks.py
def loopy(items):
    for item in items:
        print(item)
        if item == "STOP":
            break

1 Answer

James J. McCombie
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
James J. McCombie
Python Web Development Techdegree Graduate 21,199 Points

Hello,

you want to check if you should stop first, and print only if the item is not equal to 'STOP', so just a bit of rearranging, and your done with this challenge.

def loopy(items):
    for item in items:
        if item == 'STOP':
            break
        else:
            print(item)

James