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iOS Development Techdegree Student 26,430 Points"Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace! " ?
what's wrong with my solution ?
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(seq):
words = seq.lower().split(' ')
dict = {}
for word in words:
dict[word] = 0
for word in words:
dict[word]+= 1
return dict
1 Answer
Jennifer Nordell
Treehouse TeacherHi there! You're doing great, and my guess is that you've tried some test data. I'm also guessing that your test data isn't really comprehensive. Have you tried a string with any tabs or newline characters?
The challenge asks that you split on all whitespace. Currently, you are only splitting on spaces. Tabs and newlines are also whitespace.
#This splits on spaces
split(' ')
#This splits on all whitespace
split()
Removing the arguments from the split()
function causes it to split on all whitespace.
Hope this helps!
nakalkucing
12,964 Pointsnakalkucing
12,964 PointsThanks I was having trouble with this too. : )