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Vic A
5,452 Pointshonestly, i don't know where to begin on this one.
need help.
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
def combo(*args):
for x in (*args):
3 Answers
Chris Freeman
Treehouse Moderator 68,441 PointsFirst, there will be two arguments, so you can explicitly use def combo(arg1, arg2) or something similar.
One approach would be to
- loop over the length of one input argument
- use the next element of each argument to create a tuple
- append that tuple to the list that can be returned when done
- return created list
Post back if you have questions. Good luck!!!
Vic A
5,452 Pointsthanks for the help. I was successfully with this code, but I know it the scenic route to solving it. Do you know a more concise way of writing it?
def combo(x, y):
combol = []
w = 0
for i in range(len(x)):
xin = x[w]
yin = y[w]
combol.append((xin, yin))
w += 1
return combol
thanks
[MOD: added ```python formatting -cf]
Chris Freeman
Treehouse Moderator 68,441 Points# first, realize w equals i so use i instead:
def combo(x, y):
combol = []
for i in range(len(x)):
xin = x[i]
yin = y[i]
combol.append((xin, yin))
return combol
# next, can used index item directly
def combo(x, y):
combol = []
for i in range(len(x)):
combol.append((x[i], y[i]))
return combol
Otherwise, you could also use a list comprehension or the built-in function zip
# list comprehension
def combo(x, y):
return [(x[i], y[i]) for i in range(len(x))]
# Using zip() [no longer acceptable answer]
def combo(x, y):
return list(zip(x, y))
Vic A
5,452 Pointsawesome thanks.
Evan Huddleson
12,623 PointsChris, can you explain step by step exactly what is being executed in the # list comprehension?
Chris Freeman
Treehouse Moderator 68,441 PointsChris Freeman
Treehouse Moderator 68,441 PointsMoving these examples under posted answer:
Starting with Vic A's solution, this is how I'd improve it.
Otherwise, you could also use a list comprehension or the built-in function
zipChris Freeman
Treehouse Moderator 68,441 PointsChris Freeman
Treehouse Moderator 68,441 PointsAdding detail of the list comprehension solution:
I read the list comprehension as Generate a list of items where
(a, b).a" is replaced withx[i]and "b" is replaced withy[i].i" is taken from theforloop whereiis each value in the range from0to thelen(x).rangegenerator stops one short of the last element, so effectively the range is [0 to len(x) -1].So, take the index values, i, from 0 to
len(x) - 1, to build a list of tuples consisting of the ith elements fromxandycontainers