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Python Python Collections (2016, retired 2019) Dictionaries String Formatting with Dictionaries

Michael Konstantinovsky
Michael Konstantinovsky
991 Points
Posted by Michael Konstantinovsky
Michael Konstantinovsky
991 Points

How can I create a list with **?

Can't understand how to create a list Thanks

string_factory.py 
# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]
listt = [{"name":"Shalev","food":"Meat"},{"name":"Eitan","food":"chips"}]

template = "Hi, I'm {name} and I love to eat {food}!"

def string_factory(listt):
    for key in listt:
        return template.format(**key)

string_factory(listt)

3 Answers

Michael Konstantinovsky
Michael Konstantinovsky
991 Points
Michael Konstantinovsky
Michael Konstantinovsky
991 Points

Thanks a lot!!! You are right! It finally worked, I been confused with ** Great answer!

Krishna Pratap Chouhan
Krishna Pratap Chouhan
15,203 Points
Krishna Pratap Chouhan
Krishna Pratap Chouhan
15,203 Points

Yeah, its kinda tricky to understand but may be this would help you.

# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]

template = "Hi, I'm {name} and I love to eat {food}!"

def string_factory(listt):
    retString = [];
    for key in listt:
        retString.append( template.format(name=key["name"], food=key['food']));
    return retString;

So get it done using '**' operator, we could use following code and then we don't have to specify what is "name" and "food" for the template.

def string_factory(listt): 
    ret_string = [] 
    for key in listt: 
        ret_string.append(template.format(**key) );
    return ret_string 
string_factory(listt);
Michael Konstantinovsky
Michael Konstantinovsky
991 Points
Michael Konstantinovsky
Michael Konstantinovsky
991 Points

Thanks for an answer, but it still doesn't work. Here is my code:

listt = [{"name":"Shalev","food":"Meat"},{"name":"Eitan","food":"chips"}] template = "Hi, I'm {name} and I love to eat {food}!" def string_factory(listt): string = [] for key in listt: string.append(template.format(**key) return string string_factory(listt)

Krishna Pratap Chouhan
Krishna Pratap Chouhan
15,203 Points

a little problem in syntax. Seems like you missed a parenthesis for append().

listt = [{"name":"Shalev","food":"Meat"},{"name":"Eitan","food":"chips"}] 
template = "Hi, I'm {name} and I love to eat {food}!" 
def string_factory(listt): 
    string = [] 
    for key in listt: 
        string.append(template.format(**key) );
    return string 
string_factory(listt);

Please do let me know of this doesn't works, thanks.

And another important trick for treehouse: use three backtics '`' followed by language name followed by the code to share code for that language. for more details see 'Markdown Cheatsheet'.