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Richard McGrath
5,597 PointsHow come a puts statement will be executed first if not in the block or block method but placed between them?
def block_method
puts "This is the first line in block_method"
yield
puts "This statement is after the yield keyword"
end
puts "This statement is physically located between the method and block"
block_method do
puts "This statement is called from the block"
end
The output I get from running the following code is:
- This statement is physically located between the method and block
- This is the first line in block_method
- This statement is called from the block
- This statement is after the yield keyword
2 Answers
Kourosh Raeen
23,733 PointsBecause the first five lines of code are only defining the method. You are calling the block_method method after the line:
puts "This statement is physically located between the method and block"
So the very first thing that gets printed is: "This statement is physically located between the method and block"
All other puts statements get executed once the method is actually called, which is here:
block_method do
puts "This statement is called from the block"
end
Richard McGrath
5,597 PointsThis makes sense now, thank you.