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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

Rebekah McCarley
Rebekah McCarley
1,835 Points

How do I complete step 2 of this challenge?

I can't seem to figure out step 2 of this challenge. I've tried a bunch of different things and keep getting the same error -- that I'm not storing the return value in the echo variable. Can someone please review my code and tell me where I'm going wrong? I'm completely lost on this one.

script.js
function returnValue(greeting) {
  return greeting;
  var echo = 'greeting' + ' there!';
}

returnValue('Hello');
index.html
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

2 Answers

Steven Parker
Steven Parker
231,275 Points

After step 1, the function is complete. In step 2 you won't make any changes to the function, but you'll add code after the function to create the variable, and to set it using the function.

Ryan Colquhoun
Ryan Colquhoun
12,026 Points

Hi Becky,

Your answer is close, you just need to arrange the 'return' call line. I've added some code below that hopefully will help. Also, by using quote marks around 'greeting', you're creating an actual string.

function nameGreeting(firstName) {
    //create var string, and concatinate ' is my name.' to firstName
    //firstName doesn't require quotes
    var stringTogether = firstName + ' is my name.';

    //return the final string, with the variable stringTogether
    return stringTogether;
  }

//call the function 
nameGreeting('Becky');


//output is 'Becky is my name.'
Steven Parker
Steven Parker
231,275 Points

These suggestions don't go with this challenge. Perhaps you have this question confused with another part of the course?