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Python Python Basics (2015) Letter Game App Even or Odd Loop

Ping Li
Ping Li
2,689 Points
Posted by Ping Li
Ping Li
2,689 Points

How do I do this problem (Even or Odd Loop, Python) ?

Make a while loop that runs until start is falsey.

Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99.

If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole.

Otherwise, print "{} is odd", again using the random number.

Finally, decrement start by 1.

even.py 
import random
start = 5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

1 Answer

Dario Bahena
Dario Bahena
10,697 Points
Dario Bahena
Dario Bahena
10,697 Points 
# the even_odd function is already complete
# it should be noted that it returns a boolean
# if the number is even the function returns True if it's odd it returns False

import random
start = 5
def even_odd(num):
    # If num % 2 is 0, the number is even. 
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2   # returns the boolean True or False

while start: 
    randInt = random.randint(1, 99)
    if even_odd(randInt) == True:
        print("{} is even".format(randInt))
    else:
        print("{} is odd".format(randInt))
    start -= 1