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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Sean Yau
Sean Yau
1,230 Points

How do i make the code more efficient?

hi,

Would like to seek help on how to shorten the codes to be more efficient. Anyone able to help? Thank you so much!

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count (arg):
    lower_arg = arg.lower()
    split_list = lower_arg.split()
    counted_words = []
    dictionary = {}
    for word in split_list:
        if word in counted_words:
            continue
        else:
            dictionary.update({word : split_list.count(word)})
            counted_words.append(word)

    return dictionary
Igor Ević
Igor Ević
5,827 Points 
def word_count(sentence):
    words = sentence.lower().split()
    result = {}
    for word in words:
        result[word] = result.get(word, 0) + 1
    return result

1 Answer

Sean Yau
Sean Yau
1,230 Points
Sean Yau
Sean Yau
1,230 Points

Thank you