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PHP PHP Basics Daily Exercise Program String Manipulation

How do you create a new lined using \n in a string, and still have multiple tasks run individually?

I am able to get the string to output what it needs to say --- but I am getting a message saying that my second task is no longer running. I think I am placing the escape character \n in the incorrect place or with inproper syntax.

How do I go about getting a string to out put the proper information while still allowing previous tasks to run?

index.php
<?php
$firstName = 'Rasmus';
$lastName = 'Lerdorf';
$fullname = $firstName . ' ' . $lastName . ' was the original creator of PHP';

echo $fullname 
//Place your code below this comment

?>

2 Answers

Thomas Fildes
Thomas Fildes
22,687 Points

Hi Kelly,

This challenge is a real handful sometimes basically you need to echo the fullname variable with strings concatenated together to create the required sentence. Here is the correct code below:

$firstName = "Rasmus";
$lastName = "Lerdorf";
$fullname = $firstName . " " . $lastName;
echo $fullname . " was the original creator of PHP" . "\n";

If you concatenate the string 'was the creator...' to the fullname variable you achieve the sentence. Also, I have concatenated the "\n" in a string as required which creates a new line.

Hope this helps. Happy Coding!

thank you very much!

Tanja Schmidt
Tanja Schmidt
11,798 Points

The hints in the error messages are often a bit confusing. Your previous code still runs, but it causes this specific error message because you've changed the value of the variable $fullname - I had the same problem at first. ;-) In this task you are just asked to use (and not to change!) $fullname to print the string to the screen. So reset your code and echo a string that includes $fullname and remember to add the line break right after PHP with no space in between. (And enter your code below the comment - placing it above might also cause an error in the challenge though the code itself runs fine).

echo "$fullname was the original creator of PHP\n";

Thank you so much! Very helpful.