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Ruby

Posted by sebastien penot
sebastien penot
3,292 Points

How do you return/print each value of an array within a ash within an array?

From this sample code:

contact = [ {name: "Sebastien", numbers [01245131, 4574568]}]

My print_contact methods aims to print out each key and value of the hash within the contact array:

def print_contact contact.each do |index| index.each do |key, value| puts "#{key} : #{value}" end end end

The result of this method prints:

Your contact list:
name : sebastien
numbers : [10292020, 202020202]

So my question is: How do I print the value inside the array and not the array itself.

Thanks!

1 Answer

Maciej Czuchnowski
Maciej Czuchnowski
36,441 Points

Try this, without two .each methods:

contact = [ {name: "Sebastien", numbers: [01245131, 4574568]} ]

contact.each do |index| 
    puts "name : #{index[:name]}"
    puts "numbers: #{index[:numbers][0]}, #{index[:numbers][1]}"
end

This assumes that every object in the array will be formatted the same way - it will have the key :name and the key :numbers which will be an array of at least two elements.

sebastien penot
sebastien penot
3,292 Points

Thanks Maciej!

What if you don't know the length of the numbers: array?

Maciej Czuchnowski
Maciej Czuchnowski
36,441 Points

Then you can use another .each for just the numbers array. Something like this:

contact = [ {name: "Sebastien", numbers: [01245131, 4574568]} ]

def converter(array)
    number_string = ""
    array.each { |number| number_string = number_string + "#{number}" + ", " }
    return number_string
end

contact.each do |index| 
    puts "name : #{index[:name]}"
    puts "numbers: " + converter(index[:numbers])
end

Please note that 01245131 is not converted into the same number when in a string. It becomes 346713, because Ruby thinks it's an octal number (leading 0).