How do you split the string into first and second half?

Question

silly.py

# The first half of the string, rounded with round(), should be lowercased.
# The second half should be uppercased.
# E.g. "Treehouse" should come back as "treeHOUSE"
def sillycase(str):
    return round(str[])

Answer 1 · 2016-09-30T14:52:14Z

September 30, 2016 2:52pm

you function needs to first split the string in two. The issue will be that you may have even or odd number of characters in the string. Hence, if you divide the string by two to split it, you may get a float. Therefore you are going to set the first half of the string to be the rounded value of the length of the string / 2, and the second half its total length minus this value.

once you have the lengths of the first part and last part you can take slices of the string using the lengths to get the right characters and call .upper() or .lower() on the slices. You can then return the concatenated slices.

I would write something like this:

def sillycase(string):
    length_string = len(string)
    first_length = round(length_string / 2)
    first_half = string[0:first_length].lower()
    second_half = string[first_length:].upper()
    return first_half + second_half

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Erik Luo

Erik Luo

How do you split the string into first and second half?

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James J. McCombie

James J. McCombie