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Start your free trialEvan Behmlander
1,779 PointsHow is my argument not being stored in the variable?
I cannot understand why I'm getting an error saying that my argument is not being passed into the variable "echo". Very new to coding, thanks!
function returnValue (upper)
{
var echo = upper;
return echo;
}
returnValue("hello");
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
1 Answer
eck
43,038 PointsYour interpretation of this question is just a bit off. You are setting echo
inside your function, when really what the challenge is looking for is that you call returnValue
and assign the output to a variable called echo
.
Remember that when a function returns a value you can assign that value to a variable by writing the function call on the right side of the =
sign used to declare said variable.
Hopefully that explanation is enough of a nudge in the right direction :P
Evan Behmlander
1,779 PointsEvan Behmlander
1,779 PointsYes! That made it more clear. Thanks Erik!