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Python Python Collections (2016, retired 2019) Lists Disemvowel

Franchesca Lamkin
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Franchesca Lamkin
Python Web Development Techdegree Student 2,392 Points
Posted by Franchesca Lamkin
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Franchesca Lamkin
Python Web Development Techdegree Student 2,392 Points

How should I restructure this to remove the vowels?

I'm unsure how to proceed with passing this challenge and have tried various ways.

disemvowel.py 
def disemvowel(word):
    vowels=["a","e","i","o","u","A","E","I","O","U"]
    for letter in vowels:
        word.remove(letter)
    return word

1 Answer

Travis Howk
Travis Howk
7,169 Points
Travis Howk
Travis Howk
7,169 Points

I don't think that remove is the best method to be using here. Try using replace instead. For example, I could replace each of the letters that are vowels with an empty string, so something like this:

word.replace(letter, "")

Let me know if that doesn't work. Be sure to upvote it if I helped at all.

Franchesca Lamkin
seal-mask
.a{fill-rule:evenodd;}techdegree
Franchesca Lamkin
Python Web Development Techdegree Student 2,392 Points
Franchesca Lamkin
.a{fill-rule:evenodd;}techdegree
Franchesca Lamkin
Python Web Development Techdegree Student 2,392 Points

Thanks, Travis. We were given this challenge after learning remove. Here are the instructions provided...

OK, I need you to finish writing a function for me. The function disemvowel takes a single word as a parameter and then returns that word at the end. I need you to make it so, inside of the function, all of the vowels ("a", "e", "i", "o", and "u") are removed from the word. Solve this however you want, it's totally up to you! Oh, be sure to look for both uppercase and lowercase vowels!

Travis Howk
Travis Howk
7,169 Points

The problem with using the remove method is that the remove method will only remove the first instance of an item within the list. Thus, something like this could happen 

myarray = ["t","a","t"]
myarray.remove("t")
print(myarray)

=> ["a","t"]

You could fix this by making it check every single item in the word against every single vowel that you have, but that is a little time consuming (although it does work).