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Start your free trialNyasha Chawanda
7,946 Pointshow to create a function named word count that takes a string and return a dictionary
how to create a function named word count that takes a string and return a dictionary
# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.
def word_count(my_string):
string_dict={}
for wd in my_string.split():
if wd in string_dict[wd]:
string_dict[wd]+=1
else:
string_dict[wd]=1
return string_dict
2 Answers
William Li
Courses Plus Student 26,868 PointsYour code only has couple minor problems
- incorrect indentation on some lines
-
if wd in string_dict[wd]:
should beif wd in string_dict:
.
def word_count(my_string):
string_dict={}
for wd in my_string.split():
if wd in string_dict:
string_dict[wd]+=1
else:
string_dict[wd]=1
return string_dict
Paul Bentham
24,090 PointsHi,
This question has already been answered here:
https://teamtreehouse.com/forum/splitstring-not-defined-whats-wrong-here-stuck
You need to set the values to your keys in string_dict to zero first.
William Li
Courses Plus Student 26,868 PointsNo, you don't. When a word is found, it should be added to dictionary and set its value to 1. And running the for loop once is enough, no need to run it twice.
Paul Bentham
24,090 PointsYou're correct. Thanks for that :)