how to parseInt and parseFloat on one number?

Your code works, but you can simplify your code to let number = parseFloat("202.99");.

Both parseInt() and parseFloat() can convert strings to numbers. To convert "202.99" to an integer, you could use number = parseInt("202.99");, and the value for number would be 202. To convert "202.99" to a float, you could use number = parseFloat("202.99"), and the value for number would be 202.99.

In the code let number = (parseInt, parseFloat("202.99"));, JavaScript first evaluates the first expression in the parentheses, parseInt, which has no parentheses, so it refers to the function parseInt(), and is not printing anything or changing your string. JavaScript next evaluates parseFloat("202.99"), which evaluates to the number 202.99, and since it's the last item in the parentheses, its value is assigned to number.

If you wanted to chain function calls, you could do let number = parseFloat(parseInt("202.99"));, which first evaluates the inner expression parseInt("202.99"), which is 202. JavaScript then evaluates the outer expression with the result of that calculation, and so evaluates parseFloat(202), which is 202, and sets that as the value for number. You could instead do let number = parseInt(parseFloat("202.99")), which simplifies to let number = parseInt(202.99), which simplifies to let number = 202;, which is the same result, the result of let number = parseInt("202.99");. If you convert a string using the function parseInt(), you lose everything after the decimal point.