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Start your free trialEdnalyn De Dios
20,259 PointsHow to remove list within a list using conditional and type()?
Why doesn't "is not" not catching the list [1,2,3] ??? I passed by hardcoding the .remove but it feels dirty! Can somebody please tell me what's wrong?
use .remove() and/or del to remove the string, the boolean, and the list from inside of messy_list. When you're done, messy_list should have only integers in it.
messy_list = ["a", 2, 3, 1, False, [1, 2, 3]]
for item in messy_list:
if type(item) is not int:
messy_list.remove(item)
#messy_list.remove([1,2,3]) - cheating!!!!!
print(messy_list)
messy_list = ["a", 2, 3, 1, False, [1, 2, 3]]
messy_list.insert(0,messy_list.pop(3))
for item in messy_list:
if type(item) is not int:
messy_list.remove(item)
messy_list.remove([1,2,3])
print(messy_list)
1 Answer
Anibal Marquina
9,523 Pointsmessy_list = ["a", 2, 3, 1, False, [1, 2, 3]]
for _ in range(0, len(messy_list)):
for _ in messy_list:
if type(_) is not int:
messy_list.remove(_)
Anibal Marquina
9,523 PointsAnibal Marquina
9,523 PointsYou can use 'is not' as you stated before for overcoming the challenge.. but I had to be sure that the loop was iterating over the whole list...range(0, len(messy_list)). Without that line of code as you said the integers 2 and 3 are not removed from messy_list, also the same happened once with the boolean...
I tried this code also with the rest of the data types you can change the code to (bool,str,int or list) and is working
Cheers
Ednalyn De Dios
20,259 PointsEdnalyn De Dios
20,259 PointsThanks; you rock!