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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by mochammad yalinulloh
mochammad yalinulloh
Courses Plus Student 3,002 Points

how to resolve this challenge

i cant solved this challenge

in my terminal my answer is right but in challenge is not right

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(data):
    newdata = data
    dataSet = []
    x = {}
    for i in newdata.split(' '):
        c = i.lower()
        dataSet.append(c)
        x[c] = 0

    for i in x:
        x[i] = tuple(dataSet).count(i)
    print(x)


word_count("I do not like it Sam I Am")

1 Answer

KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,970 Points
KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,970 Points

Two issues

1) Your function should return a value not print.

2) You need to split on all whitespace. This is accomplished by leaving the split parameter blank. You currently have newdata.split(' '):. It should be newdata.split():.