Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
mateoniksic3
2,255 PointsHow to solve this task? (teachers and courses - max count)
Any explanation?
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(teachers):
teachers_count = len(teachers)
return teachers_count
def num_courses(teachers):
total = 0
for value in teachers.values():
total += len(value)
return total
def courses(teachers):
course = []
for value in teachers.values():
course += value
return course
def most_courses(d1):
1 Answer
Urs Merkel
Courses Plus Student 4,552 PointsHi mateoniksic3, I went with this after fighting with some errors in the exercise shell claiming it could not find mit function :D
I hope that helps you out. If you have any questions on this, just leave a comment.
Cheers, urs
def most_courses(dict_teachers):
max_c = 0
teacher_most_courses = str()
for t, c in dict_teachers.items():
if len(c) > max_c:
max_c = len(c)
teacher_most_courses = t
return teacher_most_courses