How to sort a list of tuple by the length of second element?

Question

This is for challenge 4 in Dictionary course. First, I have a dictionary like this

{'teacher1': [course1, course2], 'teacher2': [course3, course4, course5]}

then I use .items() method to create a list of tuple with teacher/course pair values. Now I want to sort them to find the teacher with most courses. But got bummer every time! I think have problem understanding how to use the .sorted() method. Can someone help me please?

teachers.py

# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers (TH_teacher):
    return len(TH_teacher)
def num_courses (TH_courses):
    course_list = []
    for course in TH_courses.values():
        course_list += course
    return len(course_list)
def courses (TH_courses):
    course_list = []
    for course in TH_courses.values():
        course_list.extend(course)
    return course_list
def most_courses (TH_courses):
    courses_list = TH_courses.items()
    new_list = sorted(courses_list, key=lambda x: x[1], reverse=True)
    return new_list[0]

Answer 1 · 2018-10-21T13:12:00Z

October 21, 2018 1:12pm

Well I am student so I could be wrong, but I do not see why do you need use sorted() method in this challange. You simply need compare teachers and find which one have more courses. I passed this challange simply looping in teachers and finding biggest lenght dictionare (d variable) and then teacher who have biggest lenght dictionare have most courses.

My code looks like this:

def most_courses(dict):
    d = 0
    n = ()
    for value1 in dict.copy():
        if len(dict[value1])> d:
            d = len(dict[value1] )
            n = value1
    return n

Hope this would help :)

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Hai Phan

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How to sort a list of tuple by the length of second element?

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Ernestas Petruoka

Ernestas Petruoka

Hai Phan

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