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Rami Bakri
782 PointsHow Xcode know which int variable is being referred to?
In this tutorial, we refer to 'int a' and 'int b'... in this case they are 'int foo' and 'int bar'.
I just want to double check my takeaway here - 'int a' is never explicitly referred to as being 'int foo'. Thus, does Xcode simply recognise the first declared int variable as int a?
I appreciate this is a super entry level question but I would just prefer to be 100% sure before moving on.
Code is below in case of need to reference.
Thanks in advance
int funky_math(int a, int b, int c);
int main() { int foo = 24; int bar = 35;
printf ("funky math %d\n", funky_math(foo, bar, check));
return 0;
}
int funky_math(int a, int b, int c) { return a + b + 343; }
2 Answers
eirikvaa
18,015 PointsWhen you declare the funky_math function before the main function, you set it to take three arguments - int a, int b and int c - in that order. Then, when you call this function inside the main function, you provide the function call with three arguments - foo, bar, check - in that order.
The variabes int a, int b and int c will be used as local variables inside the function (as seen after the main function, where you implement funky_math). When calling this function, Xcode will assign the foo variable to int a, the bar variable to int b and the check variable to int c because that's the order of the arguments you provided. If you had provided another order, Xcode would assign accordingly.
Therefore, when you call the function with the arguments foo, bar and check, Xcode knows that the value of int a will be the value that foo has at this point (same goes for the rest of the arguments).
Does this clear things up for you?
Rami Bakri
782 PointsThat did clear everything up. Thanks Eirik, super useful explanation.
eirikvaa
18,015 PointsNo problem, glad to help :)