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William Bly
6,336 Pointshttp://teamtreehouse.com/library/build-a-simple-php-application/creating-the-menu-and-footer/variables-and-conditionals
The message in the final echo command only makes sense if your favorite flavor is the same as mine. Add a conditional around that final echo command that checks if the flavor variable has a value of "cookie dough." (Remember to choose carefully between using a single equal sign and a double equal sign in the check.) Preview the code and, if you have a different flavor, make sure the message disappears.
Any with this question would be appreciated. I can't get past this step. Thank you in advance.
<?php
echo "<p>Your favorite flavor of ice cream is "; echo "vanilla"; echo ".</p>"; echo "<p>Randy's favorite flavor is cookie dough, also!</p>"; $flavor = "vanilla"; echo $flavor;
?>
1 Answer
Stone Preston
42,016 Pointsyou are going to have to use an if statement to check the value of your flavor variable.
if ($flavor == "cookie dough") {
//you need to echo the randys favorite flavor is cookie dough also line here
}
William Bly
6,336 PointsWilliam Bly
6,336 PointsThank you Stone, I changed $flavor to "cookie dough" instead of "vanilla" which worked but your answer is what I needed to know. Regards - Bill