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Python Python Basics (2015) Letter Game App Even or Odd Loop

Mint Milano
Mint Milano
3,114 Points
Posted by Mint Milano
Mint Milano
3,114 Points

I am unable to find an error in this coding challenge

i guess i did not miss any steps. if any please correct me

even.py 
import random
def even_odd(num):

    if num%2==0:
        return "the number is even"
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
start=5
while start=5:
    get=random.randint(1,99)
    number=even_odd(get)
    if number="the number is even":
        print ("{} is even".format(get))
    print ("{} is odd".format(get))
    start =start-1

2 Answers

David Hamilton
David Hamilton
21,522 Points
David Hamilton
David Hamilton
21,522 Points

Hello Kaushik,

You do not need to modify the even_odd function. You just need to call the function in your if statement. Below is the code I used to pass the challenge.

import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start:
    get = random.randint(1, 99)
    if even_odd(get):
        print("{} is even".format(get))
    else:
        print("{} is odd".format(get))
    start -= 1
Mint Milano
Mint Milano
3,114 Points
Mint Milano
Mint Milano
3,114 Points

[solved ] thanks for replying me and soving my problem.