Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by charlesmonaghan
charlesmonaghan
742 Points

I believe I did this right, but I'm not sure why it's not working?

I'm pretty sure I got everything right. But it just returns the error "Bummer! Try again!".

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count("this is a string"):
    return {'this': 1, 'is': 1, 'a': 1, 'string': 1}

2 Answers

Logan R
Logan R
22,989 Points
Logan R
Logan R
22,989 Points

I think you're reading the comments wrong. It's saying it will run your code with those parameters. 

# The function you write
def word_count(words_as_string):
    # Make a new dictionary for words and their count.
    word_dict = {}

    # Sum words
    # ...

    return word_dict

# --------------------------
# You "can't see" this code, but this is how they will call your function

word_counts = word_count("I do not like it Sam I Am")

# Expected dictionary back:
# >>> print (word_counts)
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}

Hopefully, this helps clear up question!

Christian Lamoureux
seal-mask
.a{fill-rule:evenodd;}techdegree
Christian Lamoureux
Full Stack JavaScript Techdegree Student 22,669 Points
Christian Lamoureux
.a{fill-rule:evenodd;}techdegree
Christian Lamoureux
Full Stack JavaScript Techdegree Student 22,669 Points

I also am struggling with this one here's what I have so far def word_count(value): the_dictionary = {} value = value.lower() my_list = [''.split(value)] word_list = [] for word in my_list: word_list.append(word) if word == word in word_list: word = str(word) number = [] number.append(word) length = len(number) the_dictionary.update({word: length})

    else:
        the_dictionary.update({word: 1})
        continue

return the_dictionary