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Start your free trialDaisho Komiyama
15,906 PointsI cannot solve this challenge. SQLite in "Integrating PHP with Databases" course
The library database contains a Media table with the columns media_id, title, img, format, year and category. It also contains a Genres table with the columns genre_id and genre. To join these tables, there is a Media_Genres table that contains the column media_id and genre_id Add to the following SELECT statement to JOIN the Media table and the Genres table using the joining table Media_Genres. NOTE: You will need to add the table to the WHERE clause so that the media_id column is not ambiguous.
SELECT Media.media_id, title, img, format, year, category FROM Media JOIN Genres ON Genres.genre_id, genre WHERE Media_Genres.media_id = Media_Genres.genre_id
1 Answer
Codin - Codesmite
8,600 PointsSELECT * FROM Media
JOIN Media_Genres ON Media.media_id = Media_Genres.media_id
JOIN Genres ON Genres.genre_id = Media_Genres.genre_id
WHERE Media_Genres.media_id = Media.media_id
Daisho Komiyama
15,906 PointsDaisho Komiyama
15,906 PointsIt works! Thank you Ashley!