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Python Python Basics (2015) Number Game App Squared

Posted by B.B Eight
B.B Eight
725 Points

I can't figure out what's wrong with my code. please help

def squared(num): while True: try: int(num) except ValueError: return(num*len(num)) else: return(num*num)

squared.py 
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(num):
    while True:
        try:
            int(num)
        except ValueError:
            return(num*len(num))
        else:
            return(num*num)

1 Answer

Ioannis Leontiadis
Ioannis Leontiadis
9,828 Points
Ioannis Leontiadis
Ioannis Leontiadis
9,828 Points

Hello,

when using int( String ) to a string that can be converted to an integer, i.e. "2", your try statement executes just fine but fails in the else clause when it tries to multiply the string by itself.

Try assigning the parsed string into a variable. That way if the parsing fails, the except clause will execute but if it does not you will have an integer to deal with.

For example try,

num = int( num )

Hope that helped!

B.B Eight
B.B Eight
725 Points

Thank you!!