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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Lydia O' Brien
Lydia O' Brien
4,014 Points
Posted by Lydia O' Brien
Lydia O' Brien
4,014 Points

I can't figure this out!!!!!

I have tried different solutions and even bothered to look up tips, but I can't figure it out! I been on this question for 3 days now and I can't try this question anymore for anymore times!! Help!

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(a_string):
    counts = {}
    for word in a_string.split():
Taylor Schimek
Taylor Schimek
19,318 Points
Taylor Schimek
Taylor Schimek
19,318 Points

Howdy. So far this looks right. Now, you just need to update counts inside that for loop. Also, make sure .split() has a space between the parentheses. .split( ).

1 Answer

Thomas Nilsen
Thomas Nilsen
14,957 Points
Thomas Nilsen
Thomas Nilsen
14,957 Points

you could do something like this;

def word_count(a_string):
    return {i:a_string.count(i) for i in a_string.lower().split()}