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Start your free trialsagar thakkar
902 Pointsi cant find solution i don't know where i am wrong.....
please help
messy_list = ["a", 2, 3, 1, False, [1, 2, 3]]
# Your code goes below here
del messy_list.pop(3)
messy_list.insert(0,1)
messy_list.remove("a")
messy_list.remove(False)
del messy_list[1,2,3]
print(messy_list)
2 Answers
kramer
3,515 PointsTry this
messy_list = ["a", 2, 3, 1, False, [1, 2, 3]]
messy_list.insert(0,messy_list.pop(3))
messy_list.remove(False)
messy_list.remove("a")
messy_list.remove([1, 2, 3])
Vera Dou
1,532 PointsThe line "del messy_list.pop(3)" will cause a syntax error because you can't delete a function call. Use "messy_list.pop(3)" or "messy_list.remove(1)" instead, which will do the job of removing the integer 1 from the list.
The line "del messy_list[1,2,3]" in your code will cause a TypeError beause "del" expects an index in the [] after the list name. If you want to delete the last item in the messy_list, try "del messy_list[-1]"