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Start your free trialJake Hudson
7,841 PointsI can't get around this error. not sure where it is.
"Be sure the $name parameter is assigned to the common_name property. Use $this to refer to the current object."
Perhaps I'm too sleep deprived to figure out why I can't get around this error?
<?php
class Fish {
public $common_name = "default name";
public $flavor = "default flavor";
public $record_weight = "record that weight yo.";
function __construct($name, $flavor, $record){
$this -> name = $name;
$this -> flavor = $flavor;
$this -> record = $record;
}
}
?>
2 Answers
Tommy Choe
38,156 PointsHey Jake,
I was actually making the same mistake not too long ago. You're assigning the passed parameter "$name" to a property called name. The only problem is that you don't actually have one. Yours is called $common_name. So all you need to do is change it so that you're assigning $name, $flavor, and $record to the appropriate property names.
function __construct($name, $flavor, $record){
$this -> common_name = $name;
$this -> flavor = $flavor;
$this -> record_weight = $record;
}
Let me know if you're having trouble getting through the rest of the challenge.
Robert Zeno
4,660 PointsChange
$this -> name to $this -> common_name
And
$this -> record to $this -> record_weight