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2,450 Pointsi cant solve this
<?php $flavors=array("Chocolate","Vanilla","milk");
?> <p>Welcome to Ye Olde Ice Cream Shoppe. We sell <?php echo "3"; ?> flavors of ice cream.</p> <ul> <?php foreach($flavors as $flavor){?> <li><?php echo $flavor1; ?></li> <li><?php echo $flavor2; ?></li>} </ul>
2 Answers
Ben Singer
8,621 Points<li><?php echo $flavor1; ?></li>
<li><?php echo $flavor2; ?></li>}
OK, firstly, you're calling a variable that doesn't exist. Which is $flavor - the variable containing the array is $flavors.
Secondly, you're actually technically calling two variables that don't exist - $flavor1 and $flavor2.
To call specific items in an array you need to add square brackets to the end of the array variable, so if we want to call the first two items / flavors in the array, we do this:
<li><?php echo $flavors[0]; ?></li>
<li><?php echo $flavors[1]; ?></li>
This should work.
Ted Sumner
Courses Plus Student 17,967 PointsFirst, you need to format your code quote using the Markdown Cheatsheet syntax below. It will make your code readable.
I think you are stuck on step 4. You need to substitute out the number 2 for a dynamic way that will change based on the number of items in the array. Rather than just giving you the code to quote, I will tell you that you need to use the count() function. Here is the documentation for the function. Let me know if you still have problems.
Ben Singer
8,621 PointsDO it the dynamic way. Much better.