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PHP Integrating PHP with Databases Using Relational Tables Fetching Many Relationships

Posted by melk
melk
24,762 Points

I do not understand why this is incorrect.

while ($row = $results->fetch(PDO::FETCH_ASSOC)) { $item[$row["genre_id"]][] = $row["genre"]; }

index.php 
<?php

include "helper.php";

/*
 * helper contains the following variables:
 * $item is an array that contains details about the library item
 * $results is a PDOstatement object with our genre results.
 */
while ($row = $results->fetch(PDO::FETCH_ASSOC)) {
    $item[$row["genre_id"]][] = $row["genre"];
  }

3 Answers

Joel Bardsley
Joel Bardsley
31,249 Points
Joel Bardsley
Joel Bardsley
31,249 Points

You're not far off. Referring to the $item array structure in the challenge:

array(8) {
    ...
    ["genres"]=>
    array(2) {
        [3]=>
        string(6) "Comedy"
        [16]=>
        string(6) "Sci-Fi"
    }
}

You need to add to the $item["genres"] array with a key/value pairing of "genre_id" => "genre". To add to the $item["genres"] array you can do:

$item["genres"]["key"] = "value";

Hope that helps.

Simon Coates
Simon Coates
28,694 Points
Simon Coates
Simon Coates
28,694 Points

Following seems to pass the test, i think, though at least one comment suggested a while loop.

foreach($results as $row){
  $item['genres'][$row['genre_id']] = $row['genre'];

}

I'll admit i found the wording confusing when i looked at the challenge again.

melk
melk
24,762 Points

Thanks, Simon. I used the same $item['genres'][$row['genre_id']] = $row['genre'], but in a while clause.

melk
melk
24,762 Points
melk
melk
24,762 Points

Thanks, Joel. Now I figured it out.