Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

PHP

Michal Oniszczuk
Michal Oniszczuk
579 Points

I don't get it. The result is correct for me, but for the site it's not. I don't know what to do with it.

It's php. The task is below.

Check if each student has a GPA of 4.0. If the student has a GPA of 4.0, use the student's name variable to display "NAME made the Honor Roll". If not, use the variable to display "NAME has a GPA of GPA".

''' <?php $studentOneName = 'Dave'; $studentOneGPA = 3.8;

$studentTwoName = 'Treasure'; $studentTwoGPA = 4.0;

//Place your code below this comment if($studentOneGPA == 4.0){ echo "$studentOneName made the Honor Roll"; } else{ echo "$studentOneName has a GPA of GPA"; };

if($studentTwoGPA == 4.0){ echo "$studentTwoName made the Honor Roll"; } else{ echo "$studentTwoName has a GPA of GPA"; } ?> '''

2 Answers

Mike Henry
PLUS
Mike Henry
Courses Plus Student 5,373 Points

I think you should use the variable "$studentOneName has a GPA of $studentOneGPA";