Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialandres rivera
1,009 Pointsi dont get this problem in JavaScript
Create a new function named max which accepts two numbers as arguments (you can name the arguments, whatever you would like). The function should return the larger of the two numbers.
HINT: You'll need to use a conditional statement to test the 2 parameters to see which is the larger of the two.?
function max ( 10, 8) {
var biggerNumber = 10 > 8;
if( biggerNumber > 0) {
}
return
}
1 Answer
tobiastrinkler
Full Stack JavaScript Techdegree Student 16,538 PointsHi Andres,
First of all, parameters that you pass into a function should not be integers but a regular string. You can name them whatever you want. In this example you could call them "numb1" and "numb2".
In your if statement you would then compare these two numbers like this if(numb1>numb2). your basically saying if number one is bigger than number two do what do we want to do. Well, we want to return the bigger number which means we would put the following into curly braces: { return numb1}.
Now in your else statement your basically saying if number1 is not bigger than return number two, which would look like this at the end :
function max(num1,num2){
if(num1>num2){
return num1
}
else{
return num2
}
}
brevans26
15,198 Pointsbrevans26
15,198 PointsWhy it asks for two numbers that could be whatever we want but it can't be integers?