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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Danilo Livassan
Danilo Livassan
2,199 Points

I dont get why my code dont pass

def word_count(phrase):
    if type(phrase) is not str:
        return None
    phrase = phrase.lower().strip()
    phrase = phrase.replace(',', ' ')
    phrase = phrase.replace('.', ' ')
    dict_words = {}
    phrase = phrase.split(' ')
    for word in phrase[:]:
        if word != ' ' and word != '':
            if word in dict_words:
                dict_words[word] += 1
            else:
                dict_words[word] = 1

    return dict_words

#There is my code
wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(phrase):
    if type(phrase) is not str:
        return None
    phrase = phrase.lower().strip()
    phrase = phrase.replace(',', ' ')
    phrase = phrase.replace('.', ' ')
    dict_words = {}
    phrase = phrase.split(' ')
    for word in phrase[:]:
        if word != ' ' and word != '':
            if word in dict_words:
                dict_words[word] += 1
            else:
                dict_words[word] = 1

    return dict_words

1 Answer

Brendan Chamberlain
Brendan Chamberlain
2,753 Points

hm it looks like your code works, not sure why it's not working. However it's a bit too complex. This worked for me:

def word_count(str): new_str = str.lower().split() return {i: new_str.count(i) for i in new_str}