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Enya Do
552 PointsI don't know how to solve this assignment.
how do I use the float(). Earlier in my code I tried typing float(a) float(b) right before return.
def add(a, b):
return(a+b)
c = add(5, 7)
5 Answers
Keli'i Martin
8,227 PointsYou can use float() on a and b as you're adding them and returning the result. It should look something like this:
return float(a) + float(b)
Hope this helps.
Chris Freeman
Treehouse Moderator 68,426 PointsHere is a walk-through of the challenge. For Task 2 and 3, two solutions are provided, a step-by-step version and a compressed version.
# Task 1 of 3
# I need you to make a new function, 'add'
# 'add' should take two arguments,...
def add(num1, num2):
# add them together, and return the total.
return num1 + num2
# Task 2 of 3
def add(num1, num2):
# Let's make sure we're always working with floats. Convert your
# arguments to floats before you add them together. You can do
# this with the float() function.
fl_num1 = float(num1)
fl_num2 = float(num2)
return fl_num1 + fl_num2
# Task 2 (compressed)
def add(num1, num2):
# Coversion, add, and return
return float(num1) + float(num2)
# Task 3 of 3
def add(num1, num2):
# You're doing great! Just one more task but it's a bigger one.
# Right now, we turn everything into a float. That's great so long
# as we're getting numbers or numbers as a string. We should handle
# cases where we get a non-number, though.
# Add a 'try' block before where you turn your arguments into floats.
try:
fl_num1 = float(num1)
fl_num2 = float(num2)
# Then add an 'except' to catch the possible 'ValueError'.
except ValueError:
# Inside the 'except' block, return 'None'.
return None
# If you're following the structure from the videos, add an 'else:'
# for your final return of the added floats.
else:
return fl_num1 + fl_num2
# Task 3 (commpressed)
def add(num1, num2):
try:
# try the coversion, add, and return, if successful
return float(num1) + float(num2)
except ValueError:
# return None if not sucessful
return None
Thomas Beaudry
29,084 PointsChris, that was an awesome explanation for the code challenge! Thank you so much for going into such great detail. I was lost until I read your walk-through! :)
Carlos Quevedo
5,911 PointsHi Chris,
I'm having an issue with Task 3 although my code looks similar to the one you posted. Am I doing something wrong?:
def add(num1, num2):
try:
a = float(num1)
b = float(num2)
except ValueError:
return None
else:
return(a + b)
This is return a "Try Again!" error. Thanks!
Chris Freeman
Treehouse Moderator 68,426 PointsThe code of the try block needs indenting
def add(num1, num2):
try:
a = float(num1) # <-- indent
b = float(num2) # <-- indent
except ValueError:
return None
else:
return(a + b)
Carlos Quevedo
5,911 Points*facepalm*It's always the simplest of errors. Thanks again Chris!
Venu karanam
1,484 Pointsdef add(num1, num2): try: a = float(num1) #indentation is very much important b = float(num2) #indentation is very much important except ValueError: return None else: return(a + b)
Enya Do
552 PointsEnya Do
552 PointsThanks! That was really helpful. I was able to complete the challenge.