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Python Python Basics (2015) Shopping List App Continue

sai jayanth kashyap
sai jayanth kashyap
3,293 Points
Posted by sai jayanth kashyap
sai jayanth kashyap
3,293 Points

i dont know what i am doing wrong in this question. can someone help with the error?

Same idea as the last one. My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".

breaks.py 
def loopy(items):
    # Code goes here
    for item in items:
        if item.index[0] == "a":
            continue
            else:
                print(item)

1 Answer

William Li
PLUS
William Li
Courses Plus Student 26,868 Points
William Li
William Li
Courses Plus Student 26,868 Points

Hi there. Couple things need to be fixed for the code to work properly.

  • item.index[0] isn't the correct way to find index 0 from item. item[0] is how we usually write it.
  • else clause needs to be at the same indentation level as the if clause. Yeah, indentation matters in python syntax.
def loopy(items):
    # Code goes here
    for item in items:
        if item[0] == "a":
            continue
        else:
            print(item)

Hope it helps.