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2,912 PointsI don't know what I'm doing here and the challenge is kinda confusing, please i need a hint and clear explanations
challenge : Let's write some functions to explore set math a bit more.We're going to be using this COURSES dict in all of the examples.Don't change it, though! So, first, write a function named covers that accepts a single parameter, a set of topics. Have the function return a list of courses from COURSES where the supplied set and the course's value (also a set) overlap. For example, covers({"Python"}) would return ["Python Basics"].
I need a hint no answers i didnt think this challenge was going to take me so much time.
COURSES = {
"Python Basics": {"Python", "functions", "variables",
"booleans", "integers", "floats",
"arrays", "strings", "exceptions",
"conditions", "input", "loops"},
"Java Basics": {"Java", "strings", "variables",
"input", "exceptions", "integers",
"booleans", "loops"},
"PHP Basics": {"PHP", "variables", "conditions",
"integers", "floats", "strings",
"booleans", "HTML"},
"Ruby Basics": {"Ruby", "strings", "floats",
"integers", "conditions",
"functions", "input"}
}
def covers(topics):
set_of_topics= set() #Empty set() #my set of topics
list_of_courses= set()#Empty set().
for each_course,each_topic in topics.items():
list_of_courses.update({each_course}) #str to set
set_of_topics.update(each_topic)
return list_of_courses, set_of_topics
1 Answer
Bryan Park
13,481 PointsSometime giving hints is harder than providing the answer. Hopefully the hint won't be to much.
You don't need two sets. One line of courseList = [] should be good. Your key and value are backwards in your for statement, and those are being ran against COURSES (not topics). Inside the for statement you can have a if statement to compare to see if the value matches the topic. If it does then append the courseList with the key. Then return the courseList.