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Python Python Basics (2015) Shopping List App Continue

CHENG HAO.HSUAN
CHENG HAO.HSUAN
663 Points
Posted by CHENG HAO.HSUAN
CHENG HAO.HSUAN
663 Points

I don't know where am I wrong. I have this problem. Didn't find the right items being printed. How can I do?

I have this problem. Didn't find the right items being printed.

breaks.py 
def loopy(items):
    # Code goes here
    for new_item in items:
        if new_item == "STOP":
            break
        elif new_item == "a":
          continue
    for item in items:
      print(item)
Dan Oswalt
Dan Oswalt
23,438 Points

Hi, make sure you're reading the question closely, you're gonna need to test the first letter of new_item for 'a', not the word itself

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,426 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,426 Points

Your first for loop will either break at a 'STOP', continue if a new_item is exactly and "a", or continue anyway after parsing all the items. The second for loop will simply print all the items.

The solution is to combine the two loops into one, printing as you go, but stop at a 'STOP'

def loopy(items):
    for new_item in items:
        # does this item start with "a"?
        if new_item[0] == "a":  # <-- add slide index for first char
            # Yes. continue to the next item (bypass print)
            continue
        # If did not skip to next iteration, so print item
        print(new_item)