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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Kate Bishop
Kate Bishop
1,410 Points
Posted by Kate Bishop
Kate Bishop
1,410 Points

I dont know why mines in a different order?

I dont know why mines in a different order?

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(ite):
    ite = ite.lower()
    list_1 = ite.split(" ")
    dicti = {}
    for i in list_1:
        if i not in dicti.keys():
            dicti[i] = 1
        else:
            dicti[i] += 1
    return dicti

1 Answer

Andrey Misikhin
Andrey Misikhin
16,529 Points
Andrey Misikhin
Andrey Misikhin
16,529 Points

The problem is not in order. Remove " " from split. To delete all whitespaces in the string you must use: list_1 = ite.split().