I don't try to cheat but what the example shows this code do the job

Hi Oszkár Fehér

So the code you posted is running into a ValueError: too many values to unpack error.

When args is attempted to be unpacked inside your for loop.

# Modified for example
def example_combo(*args):
    for a, b in args: # Right here we try to unpack args into TWO variables
        print(a)
        print(b)
        # Except we will get a ValueError if its not unpacking right amount.

# Kenneth gives an example of what he will call your function with.

combo([1, 2, 3], 'abc') # notice you are passing two arguments
# but each argument is technically a "packed" item containing 3 items in it.

So you are looping through each thing in args which first time through the loop will be [1, 2, 3]. It tries to unpack [1, 2, 3] into a, b but it can only get 1 and 2 out and what happens to 3? ValueError :(

If you are always expecting 3 items to unpack you could try adding another variable in for loop unpacking.

def example_combo(*args):
    for a, b, c in args: # Now we unpack into 3 variables
        print(a)
        print(b)
        print(c)

# Output should be
1
2
3
a
b
c

This isnt the answer, but it is meant to help you figure out the problem so you can get your code working. Let me know if this helps you understand whats happening.