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Python Python Collections (Retired) Dictionaries Teacher Stats

Posted by Marc Differding
Marc Differding
3,252 Points

I don't understand why my codes isn't accepted in teachers.py 3/3. It outputs the exact required values in a list.

def stats(teachersDictionary):
    teachersLt = []
    classesLt = []
    numberOfClassesLt = []
    statsLt = []
    for teacher in teachersDictionary.keys():
        teachersLt.append(teacher)
        if teacher in teachersDictionary:
            numClasses = len(teachersDictionary.get(teacher))
            classes = teachersDictionary.get(teacher)
            numberOfClassesLt.append(numClasses)
            classesLt.append(classes)
    for i in range(len(teachersLt)):
      statsLt.append(teachersLt[i])
      statsLt.append(numberOfClassesLt[i])
    return statsLt

1 Answer

Kenneth Love
STAFF
Kenneth Love
Treehouse Guest Teacher
Kenneth Love
Kenneth Love
Treehouse Guest Teacher

I updated the code challenge to better show you the output that stats() gives. Your code is good except you're not returning a list of lists (one inside list per teacher), you're only returning one list.

Marc Differding
Marc Differding
3,252 Points

Hehe, thank you. I guess I hadn't read the task correctly. I figured it out now. I now use a temporary list for the individual teacher stats and another list for the stats:

def stats2(teachersDictionary):
    teachersLt = []
    classesLt = []
    numberOfClassesLt = []
    statsLt = []
    for teacher in teachersDictionary.keys():
        teachersLt.append(teacher)
        if teacher in teachersDictionary:
            numClasses = len(teachersDictionary.get(teacher))
            classes = teachersDictionary.get(teacher)
            numberOfClassesLt.append(numClasses)
            classesLt.append(classes)
    for i in range(len(teachersLt)):
      tempLt = []
      tempLt.append(teachersLt[i])
      tempLt.append(numberOfClassesLt[i])
      statsLt.append(tempLt)
    return statsLt