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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Makan Fofana
Makan Fofana
Courses Plus Student 1,773 Points

I feel thatI have most of it, but the end is a bit challenging.

Need some help. Thank you

even.py 
import random

start = 5
def even_odd(num):
    while start:
      random.randit(1, 99)
    if num % 2 == 0:
      print("{} is even").format(random.randit())
    elif num % 2 != 0:
      print("{} is odd").format(random.randit())
    else:
      return not num % 2
      start -= 1

     # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.

1 Answer

Tim Powell
Tim Powell
1,803 Points

Your loop is a little off. Your function is already made for you so put your while loop after it. Also, replace your elif with else and remove the return statement from the loop. Here's my solution:

import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
while start > 0:
  num1 = random.randint(1, 99)
  if even_odd(num1):
    print('{} is even'.format(num1))
  else:
    print('{} is odd'.format(num1))
  start -= 1
Tim Powell
Tim Powell
1,803 Points

Thanks, Chris. I was about to fix that mistake.

Makan Fofana
Makan Fofana
Courses Plus Student 1,773 Points

Hello, this did not work for me.

Tim Powell
Tim Powell
1,803 Points

Makan, this code passes the challenge if you copy/paste. What error are you getting?