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Basile Breton
3,906 PointsI have a correct output on my console, so don't understand why I get a Bummer here, any idea?
def word_count(word): word=word.lower() word=word.split(' ') dico=dict() for item in word: dico.update({item:word.count(item)}) return dico
word_count("I do not like it Sam I Am") Out[111]: {'am': 1, 'do': 1, 'i': 2, 'it': 1, 'like': 1, 'not': 1, 'sam': 1}
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(word):
word=word.lower()
word=word.split(' ')
dico=dict()
for item in word:
dico.update({item:word.count(item)})
return dico
2 Answers
Alex Koumparos
Python Development Techdegree Student 36,887 PointsHI Basile,
Your problem is with this line:
word=word.split(' ')
On the face of it, this seems fine, especially given the example string that the challenge provides. However, there is a subtle clue about the problem in your error message:
Bummer: Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace!
Notice that the error says "splitting on all whitespace!". This is not quite the same as what you are doing, which is splitting on single spaces. To see the difference, consider the situation where the test string is "hello to the world!" (two spaces between each word) or where the test string is "hello\tworld".
Take a look at the documentation for str.split(), and look closely at the section where the documentation talks about where sep (the argument that you are making ' ') is left as the default (None).
Hopefully this will point you in the right direction.
Cheers
Alex
Basile Breton
3,906 PointsHi Alex,
Thanks a lot for your help, I get it now!
Have a nice day Basile