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Start your free trialLionel Ng
11,833 PointsI have no idea what wrong in my answer. I tested at workspace and no error.
Using the loop construct, add the current value of number to the numbers array. Inside of the loop, add 1 to the number variable. If the numbers array has more than 3 items, use the break keyword to exit the loop.
numbers = []
number = 0
# write your loop here
loop do
numbers.push(number)
number += 1
if numbers.length > 3
break
end
end
1 Answer
William Li
Courses Plus Student 26,868 PointsThe terminate condition is not correct here. It needs to be numbers.length > 2
, because number starts at value 0 and you want the loop to stop when the Array has 3 items [0,1,2].
Lionel Ng
11,833 PointsLionel Ng
11,833 PointsWow! I got it! Thank you so much! :D